2m^2+3m-13=0

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Solution for 2m^2+3m-13=0 equation: 



2m^2+3m-13=0

a = 2; b = 3; c = -13;
Δ = b2-4ac
Δ = 32-4·2·(-13)
Δ = 113
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(3)-\sqrt{113}}{2*2}=\frac{-3-\sqrt{113}}{4}
$


$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(3)+\sqrt{113}}{2*2}=\frac{-3+\sqrt{113}}{4}
$

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